greg.knese

December 6, 2007

Math 2B: Final exam info

Filed under: Math2b — gregknese @ 2:14 pm

The final exam will cover every section we have covered in class.  Refer to the course schedule:

http://gregknese.wordpress.com/math2b-fall07/schedule/

Here are some review problems from the book for the most recent material that you might want to look at (look at earlier exam posts for review problems on old material).

pg. 576:

Concept check: 1, 2, 3, 4, 6, 7

True-False: 1-7

Exercises: 1, 3, 5, 11, 13, 15, 19, 41, 45

pg. 619:

Exercises: 1, 3a, 7

pg. 732

Concept Check: 1, 2, 4, 5

True-False: 4, 6

Exercises: 1, 3, 7, 15, 19, 21, 23, 35

14 Comments »

  1. Does anyone still need help with the webwork problem 7? My answer was correct and it might be nice to get a little extra credit. Let me know.

    Comment by student — December 6, 2007 @ 7:25 pm | Reply

  2. Whoever you are, that is really nice of you. I wish there were more people like you at UCI…

    Comment by Another student — December 7, 2007 @ 1:16 pm | Reply

  3. sure. that would be nice… how do you do it?

    Comment by Math2B Student — December 7, 2007 @ 3:54 pm | Reply

  4. Ok. Mine was: h(x)=10+(0.1)(x^{1.5})
    30 ft apart
    14.9 lbs

    What you want to do is find the length of the cable. I will find half since it is symmetric. If we are right it should be larger than 15.

    Recall that arc length is equal to
    s = \int_{0}^{15} \sqrt{1 + h'(x)^2} dx

    h'(x) = 0.15 x^{1/2}
    h'(x)^2 = 0.0225x

    so
    s = \int_{0}^{15} \sqrt{1 + 0.0225x} dx
    let u = 1 + 0.0225x
    du = 0.0225dx

    s =(400/9) \int_{x=0}^{x=15} \sqrt{u} du
    s = (400/9) (2/3) (0.0225x + 1)^{3/2}\mid_{0}^{15}
    s = (800/27) [ (0.0225(15) + 1)^{3/2} - 1^{3/2} ]
    s = (800/27) [1.5468 - 1] = 16.20

    16.20 > 15 so we are ok

    now the weight is
    16.20 * 14.9 = 241.38 lb for half the cable, the total weight is then
    2 * 241.38 = 482.72 lb.

    I hope this helps.

    Comment by min — December 8, 2007 @ 9:46 pm | Reply

  5. We never did any problems like number 7 on page 732 (you recommended it though, by accident hopefully?)…should we know how to do it? If so, then how do I go about solving that problem?

    Comment by Grandmother Willow — December 8, 2007 @ 11:42 pm | Reply

  6. Grandmother Willow,
    I did several examples of sketching polar curves in videos. One way is to plot a bunch of points, and the other is to figure out what the curve is in regular (x,y) coordinates. In this case I recommend plotting a bunch of points. (Also, just to make sure you aren’t looking at “concept check” #7 are you? I was referring to “exercise” 7 on page 733 above.)

    Comment by gregknese — December 9, 2007 @ 10:48 am | Reply

  7. Thanks, I will look over the vids again…Btw, I want to concentrate on studying the big picture calculus stuff we learned this quarter…if I still don’t understand the extra credit web #7 problem, would I be ok? I don’t have time nor space in my memory to know formulas for small things like Newton’s Law of Cooling…

    Comment by Grandma — December 9, 2007 @ 11:00 am | Reply

  8. Understanding the big picture is of course important. But, the whole point of understanding the big picture is that it should make the little picture easier.

    On #7, your confusion most likely stems from the wording. Am I right? I try not to have confusing wording on exams.

    If you are memorizing Newton’s Law of Cooling, then you don’t understand Newton’s law of cooling. It says the difference between an object’s temperature and the surrounding temperature decays exponentially with time. What could be simpler?

    Comment by gregknese — December 9, 2007 @ 11:11 am | Reply

  9. Yes, you are correct. Although for plotting a bunch of points…should I just do pi to 2pi? Cuz in you examples you usually gave a domain of some sorts…

    How about I just skip Newton’s law of cooling and just hope for the best?

    Comment by GW — December 9, 2007 @ 11:43 am | Reply

  10. Is the final going to be based more heavily on the most recent stuff or is there an equal amount of everything.

    Comment by Jesus. — December 9, 2007 @ 11:51 am | Reply

  11. Dear GW,
    For polar coordinates you go from 0 to 2\pi because that takes you all the way around the circle.

    You are of course free to skip anything you like. I never advise hoping for the best though.

    Dear Jesus,
    I’d say more heavily on recent stuff.

    Comment by gregknese — December 9, 2007 @ 11:55 am | Reply

  12. Dear Greg,

    Thank you (for the question). No thanks (for the advice) because that is the most pessimistic view on life, hahahahaha. That’s why I am not majoring in math–I would like to keep my happy view on life.

    Comment by GW — December 9, 2007 @ 12:37 pm | Reply

  13. I would love to argue that my view is not pessimistic but here is not the place.

    Comment by gregknese — December 9, 2007 @ 4:32 pm | Reply

  14. Gonna have to side with Greg on this one. Hoping for the best is a poor substitute for blatantly deciding to not prepare yourself. He isn’t overly-pessimistic, but rather, you’re overly-optimistic.

    On that note, I’m absolutely defecating myself over the test tomorrow. Gonna be a looong night.. :-)

    Comment by Level — December 9, 2007 @ 7:36 pm | Reply


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