Section 14.4 « greg.knese

May 15, 2008

Filed under: math2d-spring2008 — gregknese @ 12:14 pm

This section is on surface area (of graphs of functions). The surface area of the graph $z=f(x,y)$ over a region $R$ is:

$\iint_{R} \sqrt{1+(\frac{\partial f}{\partial x}(x,y))^2 + (\frac{\partial f}{\partial y}(x,y))^2} dA$ ,

in shorthand:

$dS = \sqrt{1+ \frac{\partial z}{\partial x}^2 + \frac{\partial z}{\partial y}^2} dA$ .

Here are some recommended problems:

14.4: 1-6, 9, 10, 21-24

and here is an introductory video:

Comments (2)

Would the final problem on the video be more easily done in polar coordinates?

Comment by Alexandre Colavin — May 17, 2008 @ 10:46 am | Reply
Yes, in fact, I wouldn’t do it any other way.

Comment by gregknese — May 19, 2008 @ 8:01 am | Reply

	Leonid on Polynomials with no zeros on t…
	Leonid on AMS citing
	gregknese on Math 2D Spring 2008 Example…
	thuvan on Math 2D Spring 2008 Example…
	gregknese on Math 2D Spring 2008 Final exam…